-
The gauge configuration ensembles are generated on anisotropic lattices. The gluonic action is chosen to be the tadpole improved version [9, 10, 16, 17]
$ \begin{aligned}[b] S_g =& -\beta\sum\limits_{s<s'}\left[\frac{5}{9}\frac{{\rm{Tr}}P_{ss'}}{\gamma_g u_s^4}-\frac{1}{36}\frac{{\rm{Tr}}R_{ss'}}{\gamma_g u_s^6}-\frac{1}{36}\frac{{\rm{Tr}}R_{s's}}{\gamma_g u_s^6}\right]\\ &-\beta\sum\limits_i\left[\frac{4}{9}\frac{\gamma_g {\rm{Tr}}P_{st}}{u_s^2}-\frac{1}{36}\frac{\gamma_g {\rm{Tr}}R_{st}}{u_s^4}\right], \end{aligned} $
(1) where
$ P_{\mu\nu} $ and$ R_{\mu\nu} $ are the$ 1\times 1 $ plaquette variable and the$ 2\times 1 $ rectangular Wilson loop in the$ \mu\nu $ plane of the lattice, respectively, with$ s,\;s' $ referring to the spatial direction and$ \nu = t $ referring to the temporal direction. The tadpole parameter$ u_s $ is defined through the spatial plaquette$ u_s = \langle \dfrac{1}{3}{\rm{Re}}{\rm{Tr}}P_{ij}\rangle^{1/4} $ , and is tuned self-consistently (The tadpole parameter of the temporal gauge links is set to be$ u_t = 1 $ as usual). The parameter$ \gamma_g $ is the bare aspect ratio parameter$ \gamma_g\sim a_s/a_t $ with$ a_s $ and$ a_t $ being the lattice spacing in the spatial and temporal direction, respectively. For fermions, say, charm quarks in this work, the action is chosen to be the anisotropic version of tadpole improved tree-level clover action [10, 17, 18] proposed by the Hadron Spectrum Collaboration$ \begin{aligned}[b] S_f =& \sum\limits_{x}\bar{\psi}(x)\left[m_0+\gamma_t\hat{W}_t+\sum\limits_{s}\frac{1}{\gamma_f}\gamma_s\hat{W}_s\right.\\ &-\frac{1}{4u_s^2}\left(\frac{\gamma_g}{\gamma_f}+\frac{1}{\xi}\right)\sum\limits_{s}\sigma_{ts}\hat{F}_{ts}\\ &+\left.\frac{1}{u_s^3}\frac{1}{\gamma_f}\sum\limits_{s<s'}\sigma_{ss'}\hat{F}_{ss'}\right]\psi(x), \end{aligned} $
(2) where
$ \hat{F}_{\mu\nu} = \dfrac{1}{4}{\rm{Im}}(P_{\mu\nu }(x)) $ and the dimensionless Wilson operator reads$ \begin{aligned}[b] \hat{W}_\mu =& \nabla_{\mu}-\frac{1}{2}\gamma_\mu \Delta_{\mu},\\ \nabla_{\mu}(x) =&\frac{1}{2}\left[U_\mu (x)\delta_{x,x+\hat{\mu}}-U_\mu^\dagger(x-\hat{\mu})\delta_{x,x+\hat{\mu}}\right],\\ \Delta_{\mu}(x) =& U_\mu(x)\delta_{x,x+\hat{\mu}}+U_\mu^\dagger(x-\hat{\mu})\delta_{x,x-\hat{\mu}}-2. \end{aligned} $
(3) For the given
$ \beta $ and the bare quark mass parameter$ m_0 $ , the bare aspect ratio$ \gamma_f $ for fermions in Eq. (2) is tuned along with$ \gamma_g $ to give the physical aspect ratio$ \xi = 5 $ that is derived from the dispersion relation of the pseudoscalar ($ \eta_c $ ) meson$ \sinh^2 \frac{\hat{E}}{2} = \sinh^2 \frac{\hat{m}}{2}+\frac{1}{\xi^2} \sum\limits_i \sin^2 \frac{\hat{p}_i}{2}, $
(4) where
$ \hat{E} $ and$ \hat{m} $ are the energy and the mass of the hadron in lattice units, and$ \hat{p}_i $ is the lattice momentum$ \hat{p}_i = $ $ 2\pi n_i/L_s $ .In practice, the procedure of the tuning of parameters is very complicated, since the parameters
$ \{\beta, \gamma_g,\gamma_f,u_s,m_0\} $ are highly correlated with each other. We omit the details here and just present the final ensemble parameters in Table 1.Label $\beta$ $L_s^3\times T$ $a_s/{ \rm{fm}}$ $\xi$ $m_0$ $N_{\rm{cfg}}$ $M_{\rm{avg}}/{ \rm{GeV}}$ E1 $2.8$ $16^3\times 128$ $0.1026$ $5$ 0.0408 6000 $2.672$ E2 $2.8$ $16^3\times 128$ $0.1026$ $5$ 0.0549 6000 $3.006$ Table 1. The parameters of the gauge ensembles used in this work. The spatial lattice spacing
$a_s$ is set from the static potential and the Sommer's parameter$r_0=0.491$ fm. We use two bare quark mass parameter$m_0$ , which give the spin average masses$M_{\rm{avg}}$ of$\eta_c$ and$J/\psi$ close to the experimental values.As an exploratory study, we ignore the effect of light quarks and generate gauge configurations with
$ N_f = 2 $ flavors of degenerate charm sea quarks on an$ L^3\times T = $ $ 16^3\times 128 $ anisotropic lattice with the aspect ratio being set to be$ \xi = a_s/a_t = 5 $ . The lattice spacing$ a_s $ is determined to be$ a_s = 0.1026 $ fm through the static potential and$ r_0 = 0.491\; {\rm{fm}} $ . The bare charm quark mass parameter is set from the spin average of physical$ J/\psi $ and$ \eta_c $ masses. This lattice setup is based on two considerations: First, it is known that the signals of gluonic operators are very noisy and demand a fairly large statistics. Second, we will use the distillation method to tackle the quark annihilation diagrams (see below). -
Quark-antiquark mesons can be accessed by quark bilinear operators
$ \bar{\psi}({\boldsymbol{x}},t)K_U({\boldsymbol{x}},{\boldsymbol{y}};t) \psi'({\boldsymbol{y}},t) $ on the lattice. Theoretically, these operators can couple with all the meson states and possible multi-hadron systems which have the same quantum number. If one is interested in the lowest-lying states, the quark field$ \psi(x) $ can be spatially smeared as$ \begin{equation} \hat{\psi}_\alpha^a({\boldsymbol{x}},t) = \Phi^{ab}({\boldsymbol{x}},{\boldsymbol{y}})\psi_\alpha^b({\boldsymbol{y}},t), \end{equation} $
(5) where
$ a,b $ are color indices,$ \alpha $ refers to the Dirac spin component, and$ \Phi^{ab}({\boldsymbol{x}},{\boldsymbol{y}}) $ is the smearing function at timeslice$ t $ . Hadronic operators constructed out of smeared quark field$ \hat{\psi} $ can dramatically reduce their coupling with much higher states. In order to obtain$ \Phi^{ab} $ , we adopt the state-of-the-art approach, namely, the distillation method [14], which is briefly described as follows.The distillation method starts with solving the eigenvalue problem of the gauge covariant second order spatial Laplacian operator on each timeslice of each gauge configuration
$ \begin{equation} -\nabla_{\boldsymbol{xy}}^2(t) v_{\boldsymbol{y}}^{(n)}(t) = \lambda_n v_{\boldsymbol{x}}^{(n)}(t), \end{equation} $
(6) where the spatial Laplacian is expressed explicitly as
$ -\nabla_{\boldsymbol{xy}}^2(t) = 6\delta_{\boldsymbol{xy}}-\sum\limits_{j = 1}^3 \left( \tilde{U}_j({\boldsymbol{x}},t)\delta_{\boldsymbol{x+j,y}}+\tilde{U}_j^\dagger({\boldsymbol{x-j}},t)\delta_{\boldsymbol{x-j,y}} \right), $
(7) where
$ i,j $ are spatial indices and$ \tilde{U} $ is the stout-link smeared gauge link. After that, for a given Dirac index$ \alpha $ , each eigenvector$ v_{\boldsymbol{y}}^{(n)}(t) $ is used as the source vector to solve the linear equation array$ \begin{equation} M_{\beta\delta}({\boldsymbol{z}},t'';{\boldsymbol{x}},t')S_{\delta\alpha}({\boldsymbol{x}},t';{\boldsymbol{y}},t)v_{\boldsymbol{y}}^{(n)}(t) = v_{\boldsymbol{z}}^{(n)}(t'')\delta_{\beta\alpha} \end{equation}, $
(8) where the matrix
$ M $ is the Dirac matrix of fermions on the lattice and$ S = M^{-1} $ is the corresponding fermion propagator. This procedure is repeated for all the Dirac indices$ \alpha = 1,2,3,4 $ , the timeslices$ t\in [0,T-1] $ and the number of the eigenvectors$ N $ . Finally, multiplying the eigenvectors$ v^{(n'),\dagger}_{\boldsymbol{x}}(t') $ to each of the solution vectors$ S_{\delta\alpha}({\boldsymbol{x}},t';{\boldsymbol{y}},t)v_{\boldsymbol{y}}^{(n)}(t) $ one gets for given$ t',\;t $ and$ \delta,\;\alpha $ the matrix elements in the subspace expanded by the$ N $ eigenvectors,$ \begin{equation} \tau_{\delta\alpha}^{n'n}(t',t) = v_{\boldsymbol{x}}^{(n'),\dagger}(t')S_{\delta\alpha}({\boldsymbol{x}},t';{\boldsymbol{y}},t)v_{\boldsymbol{y}}^{(n)}(t), \end{equation} $
(9) which are usually called perambulators. Based on these perambulators, we can define a propagating matrix
$ \begin{aligned}[b] P_{\alpha\beta}({\boldsymbol{x}},t;{\boldsymbol{y}},t') = & \sum\limits_{n,n' = 1}^N v_{\boldsymbol{x}}^{(n)}(t)\tau_{\alpha\beta}^{nn'}(t,t')v_{\boldsymbol{y}}^{(n'),\dagger}(t')\\ \equiv&\Phi({\boldsymbol{x}},{\boldsymbol{u}};t)S_{\alpha\beta}({\boldsymbol{u}},t;{\boldsymbol{v}},t')\Phi({\boldsymbol{v}},{\boldsymbol{y}};t') \end{aligned} $
(10) with
$ \begin{equation} \Phi({\boldsymbol{x}},{\boldsymbol{y}};t) = \sum\limits_{n = 1}^N v_{\boldsymbol{x}}^{(n)}(t)v_{\boldsymbol{y}}^{(n),\dagger}(t)\equiv \left[V(t)V^\dagger(t)\right]_{\boldsymbol{xy}}, \end{equation} $
(11) being the desired smearing function, where
$ V $ is a$ 3V_3\times N $ matrix with each column being one of the eigenvectors$ v^{(n)}(t) $ for$ n = 1,2,\ldots, N $ and the row number$ 3V_3 $ referring to all the spatial points and color indices. Obviously the propagating matrix$ P_{\alpha\beta}({\boldsymbol{x}},t;{\boldsymbol{y}},t') $ can be viewed as the propagator of the smeared quark field$ \hat{\psi}_\alpha({\boldsymbol{x}},t) = $ $ \Phi({\boldsymbol{x}},{\boldsymbol{y}},t)\psi_\alpha({\boldsymbol{y}},t) $ in the background gauge field$ \{U_\mu(x)\} $ , namely,$ \begin{equation} P_{\alpha\beta}({\boldsymbol{x}},t;{\boldsymbol{y}},t') = \langle \hat{\psi}_\alpha({\boldsymbol{x}},t) \bar{\hat{\psi}}_\beta({\boldsymbol{y}},t')\rangle_{U}. \end{equation} $
(12) Note that if
$ N = 3V_3 $ , then the completeness of$ v^{(n)}(t) $ implies that$ \Phi({\boldsymbol{x}},{\boldsymbol{y}};t) = \delta_{\boldsymbol{xy}}\otimes I_{\rm{color}} $ , such that$ P_{\alpha\beta}(x,y) $ is actually the all-to-all propagator of the original fermion field$ \psi $ . One can define the norm of the smearing function$ \begin{equation} \Psi(|{\boldsymbol{x-y}}|) = \sum\limits_t\left[{\rm{Tr}}\Phi({\boldsymbol{x}},{\boldsymbol{y}};t)\Phi({\boldsymbol{y,x}};t)\right]^{1/2} \end{equation} $
(13) to measure the degree to which the quark field is smeared. Due to the translational and the rotational invariance,
$ \Psi(r) $ can be averaged over all the coordinates$ {\boldsymbol{x}},{\boldsymbol{y}} $ that satisfying$ r = |{\boldsymbol{x-y}}| $ . It is easy to see that, if all the eigenvectors are involved in defining$ \Phi({\boldsymbol{x}},{\boldsymbol{y}};t) $ , then the completeness and the orthogonalization require$ \Psi(r)\propto \delta(r) $ . If the number of eigenvectors involved is truncated to be$ N<3V_3 $ , then$ \Psi(r) $ is smeared from a delta function to a function falling off rapidly with respect to$ r $ . Figure 1 shows the profiles of$ \Psi(r) $ in data points at$ N = 10, \;30, \;50 $ and 100, where$ \Psi(r) $ damps faster when$ N $ becomes bigger, and the dashed curves are naive fits using Gaussian function forms in the interval$ r/a_s\in [0,6] $ . We take$ N = 50 $ in this study.Figure 1. (color online) The profiles of the smearing function
$ \Psi(r) $ of quark fields. The data points are the values of$ \Psi(r) $ with the number of the eigenvectors of the spatial Laplacian$ N = $ 10, 30, 50 and 100. The dashed curves are naive fits using Gaussian function forms in the interval$ r/a_s\in [0,6] $ . We take$ N = 50 $ in this study.Now consider meson operators constructed out of the smeared quark field,
$ \begin{aligned}[b] {\cal{O}}_A(t) =& \bar{\hat{\psi}}({\boldsymbol{x}},t)K_U^A({\boldsymbol{x}},{\boldsymbol{y}};t) \hat{\psi}({\boldsymbol{y}},t),\\ {\cal{O}}_B(t) =& \bar{\hat{\psi}}({\boldsymbol{x}},t)K_U^B({\boldsymbol{x}},{\boldsymbol{y}};t) \hat{\psi}({\boldsymbol{y}},t), \end{aligned} $
(14) which have the same quantum number
$ J^{PC} $ . The connected part of their correlation function can be expressed as$ \begin{aligned}[b] C_{AB}(t,t') =& -{\rm{Tr}}\Big[ P({\boldsymbol{x}},t;{\boldsymbol{y'}},t')K_U^B({\boldsymbol{y',y}};t')\\&\times P({\boldsymbol{y}},t';{\boldsymbol{x'}},t)K_U^A({\boldsymbol{x',x}};t) \Big]\\ = & -{\rm{Tr}}\Big[\Phi({\boldsymbol{x,u}};t)S({\boldsymbol{u}},t;{\boldsymbol{v}},t')\Phi({\boldsymbol{v,y'}};t')\\&\times K_U^B({\boldsymbol{y',y}};t') \Phi({\boldsymbol{y,w}};t')S({\boldsymbol{w}},t';{\boldsymbol{z}},t)\\&\times\Phi({\boldsymbol{z,x'}};t)K_U^A({\boldsymbol{x',x}};t)\Big]\\ =& -{\rm{Tr}}\Big[V^\dagger({\boldsymbol{x'}},t)K_U^A({\boldsymbol{x'}},{\boldsymbol{x}},t) V({\boldsymbol{x}},t) \tau(t,t')\\&\times V^\dagger({\boldsymbol{y'}},t')K_U^B({\boldsymbol{y'}},{\boldsymbol{y}},t')V({\boldsymbol{y}},t')\tau(t',t) \Big]\\ \equiv& -{\rm{Tr}}\left[\phi^A(t)\tau(t,t')\phi^B(t')\tau(t',t)\right], \end{aligned} $
(15) where
$ \begin{equation} \phi^{A,B}(t) = V^\dagger({\boldsymbol{x}},t)K_U^{A,B}({\boldsymbol{x}},{\boldsymbol{y}},t)V({\boldsymbol{y}},t), \end{equation} $
(16) is the characteristic kernel that reflects completely the structure and the properties of operator
$ {\cal{O}}^{A,B}(t) $ . The last equation of Eq. (15) is the generic expression for mesonic two-point functions in the distillation method, where the perambulator$ \tau(t,t') $ is universal and the information of the meson operators are completely encoded in$ \phi^{A,B}(t) $ . The disconnected part of the correlation function can be similarly derived in terms of$ \phi^{A,B}(t) $ and$ \tau(t,t') $ as follows$ \begin{equation} D_{AB}(t,t') = {\rm{Tr}}\left[\phi^A(t)\tau(t,t)\right]{\rm{Tr}}\left[\phi^B(t')\tau(t',t')\right]. \end{equation} $
(17) Finally, the full correlation function of
$ {\cal{O}}^A(t) $ and$ {\cal{O}}^B(t') $ is$ \begin{equation} G_{AB}(t,t') = C_{AB}(t,t')+D_{AB}(t,t'). \end{equation} $
(18) The Eq. (18) is the basic expression we apply to calculate the corresponding correlation functions of
$ 1S $ and$ 1P $ charmonia.There are subtleties in considering the contribution from the annihilation diagrams to the charmonium masses since there are two degenerate sea quark flavors in this work. This means there is a
$ SU(2) $ global flavor symmetry, named as the isospin symmetry in principle. Thus the connected part of the correlation functions are actually$ C_{ij}(t) = \frac{1}{2}C_{ij}^{ I = 0}(t)+\frac{1}{2}C_{ij}^{I = 1}(t)\equiv C_{ij}^{I = 0}(t), $
(19) if the flavor wave functions of
$ I = 0,1 $ are taken as$ \dfrac{1}{\sqrt{2}}(\bar{c}c\pm\bar{c}'c') $ . Similarly the disconnected part should be$ \begin{equation} D_{ij}(t) = \frac{1}{2}D_{ij}^{I = 0}(t), \end{equation} $
(20) since gluons are isospin singlets and couple only with
$ I = 0 $ states. Therefore, the full correlation function of the$ I = 0 $ states is$ \begin{equation} G_{ij}^{I = 0}(t) = C_{ij}(t)+2D_{ij}(t). \end{equation} $
(21) A special attention should be paid to the
$ 0^{++} $ channel. The quark loops in this channel have nonzero vacuum expectation values and should be subtracted. For this we adopt a 'time-shift' subtraction scheme [10] by redefining the correlation function as$ \begin{equation} \tilde{G}^{0^{++}}(t) = G^{0^{++}}(t)-G^{0^{++}}(t+\delta t), \end{equation} $
(22) where the vacuum constant term cancels. In practice, we choose
$ \delta t = 5 $ . The price we pay for this is a little loss in the signal-to-noise ratio. -
As the first step, we compare the relative magnitudes of the contribution of the annihilation diagram to the connected counterpart in each channel, which is measured by the ratio for a specific channel labeled by
$ \Gamma $ $ \begin{equation} R^\Gamma(t)\equiv \frac{2D_{11}^\Gamma(t)}{C_{11}^\Gamma(t)}, \end{equation} $
(23) where the subscript '11' refers to the correlation function of the
$ |r|/a_s = 0 $ operator in the operator set of the$ \Gamma $ channel. The explicit operators are tabulated in Table 2. The ratios$ R^\Gamma(t) $ at the two quark masses are shown in Fig. 2 and Fig. 3 for channels with$J^{PC} = 0^{-+}, 1^{--}, (0,1,2)^{++}$ and$ 1^{+-} $ . It is seen that the magnitudes of$ R^\Gamma (t) $ are of order$ {\cal{O}}(10^{-3}-10^{-5}) $ : The$ R^\Gamma (t) $ 's of$ 0^{-+} $ ,$ 0^{++} $ and$ 2^{++} $ channels are much larger than those of the other three channels. This is understandable since the charm quark loops in$ 0^{-+},0^{++} $ and$ 2^{++} $ channels are mediated by two gluons to the lowest order of QCD, while the charm quark loops in other three channels are mediated by at least three-gluon intermediate states. On the other hand, the disconnected part of$ 0^{-+} $ can be also enhanced by the QCD$ U_A(1) $ anomaly. Especially, the$ R^\Gamma(t) $ of$1^{--}$ is two orders of magnitude smaller and turns out to be approximately independent of$ t $ .Figure 2. (color online) The ratio functions
$ R(t) $ for the six channels$J^{PC} = 0^{-+},1^{--},(0,1,2)^{++}$ and$ 1^{+-} $ on gauge ensemble E1. The shaded curves with error bands are the fit results using the linear part of Eq. (30) for$1^{--},\;1^{+\pm},\;2^{++}$ channels and the results for$ 0^{\pm +} $ channels using Eq. (32). The darker regions indicate the fit time range.$J^{PC}$ $0^{-+}$ $1^{--}$ $0^{++}$ $1^{++}$ $1^{+-}$ $2^{++}$ $\Gamma$ $\gamma_5$ $\gamma_i$ $I$ $\gamma_5\gamma_i$ $\epsilon_{ijk}\sigma_{jk}$ $|\epsilon_{ijk}|\gamma_j\nabla_k$ $1S, 1P$ $\eta_c$ $J/\psi$ $\chi_{c0}$ $\chi_{c1}$ $h_c$ $\chi_{c2}$ Table 2. The gamma matrix combinations
$\Gamma$ for the$J^{PC}$ channels corresponding to$1S$ and$1P$ states.Figure 3. (color online) The ratio functions
$ R(t) $ for the six channels$J^{PC} = 0^{-+},1^{--},(0,1,2)^{++}$ and$ 1^{+-} $ on gauge ensemble E2. The shaded curves with error bands are the fit results using the linear part of Eq. (30) for$1^{--},\;1^{+\pm}, \;2^{++}$ channels and the results for$ 0^{\pm +} $ channels using Eq. (32). The darker regions indicate the fit time range.The contribution of the disconnected diagrams to charmonium masses can be estimated as follows. For convenience, we drop the superscript '
$ \Gamma $ ' temporarily in the following discussion. Usually the connected part of the charmonium correlation functions and the full correlation functions can be parameterized as$ \begin{aligned}[b] C(t) =&\sum\limits_i \frac{W_i}{2m_i} {\rm e}^{-m_i t},\\ G(t) = &\sum\limits_i \frac{\tilde{W}_i}{2\tilde{m}_i} {\rm e}^{-\tilde{m}_i t}. \end{aligned} $
(24) Since
$ G(t) = C(t)+2D(t) $ , the ratio of the disconnect part to the connected part can be expressed as$ R(t) = \frac{2D(t)}{C(t)}\equiv \frac{\displaystyle\sum\limits_i \frac{\tilde{W}_i}{2\tilde{m}_i} {\rm e}^{-\tilde{m}_i t}}{\displaystyle\sum\limits_i \frac{W_i}{2m_i} {\rm e}^{-m_i t}}-1. $
(25) Intuitively, each mass term in the correlation function
$ C(t) $ is given by the propagator in the momentum space, namely,$ W_i/(p^2-m_i^2) $ . When the disconnected diagrams are considered, the propagator acquires a self-energy correction$ -\Sigma(p^2) $ , which is independent of the states. Thus the full propagator contributing to each term of$ G(t) $ can be expressed as$ \begin{aligned}[b] \frac{\tilde{W}_i}{p^2+\tilde{m}_i^2}\equiv&\frac{W_i}{p^2+m_i^2+\Sigma(p^2)}= \frac{W_i}{p^2+m_i^2}\\&+\frac{\sqrt{W_i}}{p^2+m_i^2} (-\Sigma(p^2))\frac{\sqrt{W_i}}{p^2+m_i^2} + \frac{\sqrt{W_i}}{p^2+m_i^2} (-\Sigma(p^2))\\&\times\frac{1}{p^2+m_i^2}(-\Sigma(p^2))\frac{\sqrt{W_i}}{p^2+m_i^2}+\cdots \end{aligned} $
(26) with the relations
$ \begin{aligned}[b] \tilde{W}_i = & W_i\left(1-\frac{{\rm d}\Sigma(p^2)}{{\rm d}p^2}|_{p^2 = -\tilde{m}_i^2}\right)\equiv W_i(1+\epsilon_i),\\ \tilde{m}_i^2 = & m_i^2 +\Sigma(-\tilde{m}_i^2). \end{aligned} $
(27) Based on the OZI rule and from the observation in Fig. 2 and Fig. 3, it is safe to assume
$ \epsilon_i\ll 1 $ and$\delta m_i = $ $ \tilde{m}_i-m_i\ll m_i$ . Thus we have$ \begin{equation} \delta m_i = \frac{\Sigma(-\tilde{m}_i^2)}{2m_i}\approx \frac{m_1}{m_i}\left[\delta m_1+\Delta_{i}\left(1+\frac{\Delta_i}{2m_1}\right)\epsilon_1\right], \end{equation} $
(28) where
$ \Delta_i = m_i-m_1 $ has been defined and$ \Sigma(p^2) $ is assumed to be varying very slowly with respect to$ p^2 $ . The latter is obviously justified by the observation that$ R(t) $ is usually of order$ {\cal{O}}(10^{-3}) $ or even smaller. If we assume$ \epsilon_i $ is insensitive to$ p^2 $ in the energy range of interest, we can take the approximation$ \epsilon_i\approx \bar{\epsilon} $ and$ \delta m_i\approx \dfrac{m_1}{m_i}\delta m_1 $ , which imply$ \begin{equation} \tilde{\Delta}_i = \tilde{m_i}-\tilde{m}_1\approx \Delta_i\left(1-\frac{\delta m_1}{m_i}\right)\approx \Delta_i. \end{equation} $
(29) Thus we have
$ \begin{aligned}[b] R(t)\approx & -\delta m_1 t +\epsilon_1-\frac{\delta m_1}{m_1}\\ &+F(t)\frac{\delta m_1}{m_1} \sum\limits_{i>1} \frac{W_i m_1\Delta_i}{W_1 m_i^2}{\rm e}^{-\Delta_i t}+\cdots \end{aligned} $
(30) where
$ \begin{equation} F(t) = \left[1+\sum\limits_{i>1} \frac{W_i m_1}{W_1 m_i}{\rm e}^{-\Delta_i t}\right]^{-1}. \end{equation} $
(31) The last term in Eq. (30) will die out when
$ t $ increases. Therefore, if$ R(t) $ shows up a linear dependence on$ t $ in a time region, the contribution of the disconnected diagrams to the ground state mass, namely,$ \delta m_1 $ , can be extracted by the slope of$ R(t) $ in this region.From Fig. 2 and Fig. 3, one can see that, for the
$ (1,2)^{++} $ ,$1^{--}$ and$ 1^{+-} $ channels,$ R(t) $ does show linear behaviors in different time regions. Therefore, in these time windows, we can drop the last term in Eq. (30) and fit$ R(t) $ using linear functions. The fit results are shown in these plots by curves with error bands, where the bands in darker colors illustrate the fit time window$ [t_{\rm{min}},t_{\rm{max}}] $ (the values of$ t $ are in the lattice unit$ a_t $ in the context). The fitted slopes$ \delta m_1^\Gamma a_t $ and the$ \chi^2/{{dof}} $ 's on the two ensembles (labeled as E1 and E2) are listed in Table 3 along with the$ \chi^2/{{dof}} $ in the fitting time window$ [t_{\rm{min}},t_{\rm{max}}] $ given in the table. It should be noted that the large errors of the ratio function$ R(t) $ come from the disconnected diagram which becomes very noisy beyond$ t\sim 10 $ . In the$1^{--}$ channel,$ R(t) $ shows good linear behavior in the time interval$ t\in [4,9] $ (very close to a constant) on both ensemble E1 and E2, so we attribute the behavior of$ R(t) $ in the interval$ [9,14] $ to be mostly statistical fluctuations. Actually, the data points in this interval deviate from the linear behaviors determined from the interval$ t\in [4,9] $ by less than$ 2\sigma $ . If we include the data points in the interval$ t\in [10,14] $ to the fit, the central value does not change by much with a mildly larger$ \chi^2/{{dof}} $ . Actually on E2 ensemble, all the data points in the interval$ [4,14] $ converge to a single line.$ \eta_c(0^{-+}) $ $J/\psi(1^{--})$ $ \chi_{c0}(0^{++}) $ $ \chi_{c1}(1^{++}) $ $ \chi_{c2}(2^{++}) $ $ h_c(1^{+-}) $ $ [t_{\rm{min}},t_{\rm{max}}] $ $ [5,20] $ $ [4,9] $ $ [3,14] $ $ [7,14] $ $ [5,10] $ $ [3,13] $ $\delta m_1^\Gamma a_t \;{{ (E1)} }$ 0.00031(1) $ \sim10^{-6} $ 0.007(5) 0.00014(2) −0.00031(3) 0.00010(1) $\chi^2/{{dof} }$ 1.5 0.78 0.62 0.59 0.82 0.71 $ [t_{\rm{min}},t_{\rm{max}}] $ $ [6,20] $ $ [4,14] $ $ [3,14] $ $ [6,14] $ $ [4,10] $ $ [4,13] $ $\delta m_1^\Gamma a_t \; {{(E2)} }$ 0.00032(2) $ \sim10^{-6} $ 0.003(4) 0.00006(2) −0.00029(2) 0.00012(2) $\chi^2/{{dof} }$ 1.4 0.59 1.2 0.64 0.71 1.3 Table 3. The mass shifts
$ a_t\delta m_1 $ for all the six channels. The fit time ranges$ [t_{\rm{min}},t_{\rm{max}}] $ and the values of the$ \chi^2 $ per degree of freedom ($ \chi^2/{{dof}} $ ) are also presented.Obviously, the
$ \delta m_1 $ of the$ J/\psi $ is tiny and consistent with zero within the errors. This can be understood as the result of the strong suppression based on the Okubo-Zweig-Iizuka rule (OZI rule) [4-6], since the two charm quark loops are mediated by at least three intermediate gluons. For$ \chi_{c1} $ and$ h_c $ , the mass shifts due to the charm annihilation effect are small but non-zero. This is understandable since the contribution of two-gluon intermediate states is suppressed to some extent due to the Landau-Yang theorem [19, 20]. It is surprising that this kind of mass shift of$ \chi_{c2} $ is relatively large and negative. The reason for this is not clear yet. Intuitively, lattice QCD studies predict that the lowest tensor glueball mass is approximately 2.2–2.4 GeV [8-10, 21, 22], which is lower than the$ \chi_{c2} $ mass and should result in positive mass shift if$ \chi_{c2} $ and the tensor glueball can mix.The situation of the scalar and the pseudoscalar channels is a little more complicated. It is seen in Fig. 2 and Fig. 3 that the ratio functions
$ R(t) $ in these two channels increase rapidly when$ t $ is large. This observation signals that there may be lighter states than the ground state charmonium contributing to the correlation function$ G(t) $ in the scalar and pseudoscalar channels. Actually, lattice QCD calculations predict that the masses of the lowest scalar and the pseudoscalar glueballs are 1.5–1.7 GeV and 2.4–2.6 GeV [8-10, 21, 22], respectively. When the disconnected diagrams are considered, these glueballs can contribute as intermediate states to the correlation function$ G(t) $ . Therefore, more mass terms should be added into the expression of$ G(t) $ (Eq. (24)) to account for the possible contribution from glueballs. Consequently, Eq. (25) for these two channels may be modified to$ \begin{equation} R'(t)\approx R(t)+W_g {\rm e}^{\Delta_g t}, \end{equation} $
(32) where
$ \Delta_g = m_1-m_{\rm G}>0 $ is a parameter resembling the mass difference between the ground state glueball and the corresponding charmonium state. Of course, one-glueball or multi-glueball states (if they exist) can also appear in other channels, but Fig. 2 and Fig. 3 show that their contributions have no sizable effects and can be ignored in practice.We tentatively use the functions form of Eq. (32) to fit
$ R(t) $ of the scalar and the pseudoscalar channels, with$ R(t) $ in this equation being approximated by a linear function. The fit results are illustrated in Fig. 2 and Fig. 3 by curves with error bands, where one can see that the function form describes the data very well in large time ranges. This manifests the efficacy and the necessity of the second term in Eq. (32). The mass shift$ \delta m_1 $ of the ground state pseudoscalar charmonium$ \eta_c $ is determined to be +3.0(1) MeV for E1 ensemble and +3.1(2) MeV for E2 ensemble, respectively.$ \delta m_1 $ is converted into the value in physical units using the temperal lattice spacing$ a_t^{-1} = 9.62 $ GeV. This result is consistent with the previous result in Ref. [13] and the result$ \delta m_1 = 3.9(9) $ MeV derived from the glueball-charmonium mixing mechanism [23].The values of the
$ \chi_{c0} $ mass shift are fitted to be 67(48) MeV for E1 ensemble and 29(38) MeV for E2 ensemble, respectively. The results for$ \chi_{c0} $ have large errors due to the nonexistence or shortness of the linear behavior. Due to the large error, we cannot get a reliable final result of the$ \delta m_1 $ for$ \chi_{c0} $ .Using the lattice spacing
$ a_t^{-1}\approx 9.62 $ GeV, we get the mass shifts$ \delta m_1 $ as follows:$ \begin{aligned}[b] {{E1}}:\; \; \; \;\;\;\; \delta m_1 (0^{-+}) =& 3.0(1)\; \; {\rm{MeV}},\\ \;\;\;\; \delta m_1 (1^{++}) = &1.3(2)\; \; {\rm{MeV}},\\ \;\;\;\; \delta m_1 (2^{++}) =& -3.0(3)\; \; {\rm{MeV}},\\ \;\;\;\; \delta m_1 (1^{+-}) =& 1.0(1)\; \; {\rm{MeV}}.\\ {{E2}};\; \; \; \;\;\;\; \delta m_1 (0^{-+}) =& 3.1(2)\; \; {\rm {MeV}},\\ \;\;\;\; \delta m_1 (1^{++}) =& 0.6(2)\; \; {\rm{MeV}},\\ \;\;\;\; \delta m_1 (2^{++}) =& -2.8(2)\; \; {\rm{MeV}},\\ \;\;\;\; \delta m_1 (1^{+-}) =& 1.2(2)\; \; {\rm{MeV}}. \end{aligned} $
(33) Since the fitted
$\delta m_1(1^{--})$ is very small, we do not quote its value here but only say that the charm annihilation effects in$1^{--}$ are negligible. The mass shifts$ \delta m_1 $ from E1 and E2 ensembles are compatible with each other in most channels except for the$ 1^{++} $ channel, where the deviation of$ \delta m_1 $ values on the two ensembles is larger than$ 3\sigma $ . The reason for this discrepancy is not clear yet and should be investigated in the future. -
Now that we have calculated the perambulators of charm quarks on the two gauge ensembles of large statistics, we would like to take a look at the charmonium spectrum. In this work, we will focus on the lowest two states in
$J^{PC} = 0^{-+},1^{--},(0,1,2)^{++}$ and$ 1^{-+} $ channels. In the previous sections we have shown that the inclusion of the disconnected diagrams does not change the masses of charmonium states much, so in the following discussions we only consider the connected part of the correlation functions. For each$ J^{PC} $ quantum number, we will first build an operator set, then calculate the correlation matrix of the operators in this set. After that, we will solve the generalized eigenvalue problem (GEVP) to obtain the optimized operators that couple most to specific states. What follows are the technique details. -
As we addressed in Sec. II.B, the distillation method automatically provides the gauge covariant smearing function
$ \Phi^{ab}({\boldsymbol{x}},{\boldsymbol{y}}) $ for quark fields on each timeslice. To be specific, the smeared quark field$ \hat{c}({\boldsymbol{x}},t) $ can be obtained by$ \hat{c}^a({\boldsymbol{x}},t) = \Phi^{ab}({\boldsymbol{x}},{\boldsymbol{y}}) c^b({\boldsymbol{y}},t) $ , where the duplicated spatial coordinate$ {\boldsymbol{y}} $ means the summation over the space volume. Thus, the quark bilinear operators for meson states in this study can be built in terms of the smeared charm quark field$ \hat{c}(x) $ . We introduce the spatially extended operators for each channel as$ \begin{equation} {\cal{O}}(r,t) = \frac{1}{N_r}\sum\limits_{{\boldsymbol{x}},|{\boldsymbol{r}}| = r}\bar{\hat{c}}({\boldsymbol{x}},t)K_U^\Gamma({\boldsymbol{x,x+r}};t)\hat{c}({\boldsymbol{x+r}},t), \end{equation} $
(34) where
$ N_r $ is the multiplicity of$ {\boldsymbol{r}} $ with$ |{\boldsymbol{r}}| = r $ , and$ \begin{equation} K_U^\Gamma({\boldsymbol{x,x+r}};t) = \Gamma {\cal{P}}{\rm e}^{-{\rm i}g\int_{{\boldsymbol{x}}}^{{\boldsymbol{x+r}}} {\boldsymbol{A}}\cdot {\rm d}{\boldsymbol{r}}}\equiv \Gamma {\cal{L}}({\boldsymbol{x,x+r}};t) \end{equation} $
(35) with
$ \Gamma $ being the specific combination of$ \gamma $ -matrix that gives the right quantum number of each of the$ 1S $ and$ 1P $ state (the explicit expressions of$ \Gamma $ 's are tabulated in Table 2), and$ {\cal{L}}({\boldsymbol{x,x+r}};t) $ being the gauge transportation operator from$ ({\boldsymbol{x}},t) $ to$ ({\boldsymbol{x+r}},t) $ . Obviously,$ {\cal{O}}(r,t) $ is gauge invariant. Thus one can get the kernel function$ \begin{equation} \phi^{r}(t) = \frac{1}{N_r}\sum\limits_{{\boldsymbol{x}},|{\boldsymbol{r}}| = r}V^\dagger({\boldsymbol{x}},t)K_U^\Gamma({\boldsymbol{x,x+r}};t)V({\boldsymbol{x+r}},t). \end{equation} $
(36) Because the disconnected part is considerably smaller than the connected part and has little effect on present discussion, the correlation function
$ G_{ij}(t) $ can be approximated by their connected part as$ G_{ij}(t) = \frac{1}{T}\sum\limits_{t_0 = 0}^{T-1} \langle {\cal{O}}(r_i,t+t_0){\cal{O}}(r_j,t_0)\rangle \approx C_{ij}(t), $
(37) where
$ C_{ij}(t) $ is the connected part$ \begin{aligned}[b] C_{ij}(t) =& -\frac{1}{T}\sum\limits_{t_0 = 0}^{T-1}\left\langle{\rm{Tr}}\left[\phi^{r_j}(t+t_0)\tau(t+t_0,t_0)\right.\right.\\ &\times \left.\left.\phi^{r_i}(t_0)\tau(t_0,t+t_0)\right]\right\rangle. \end{aligned} $
(38) In practice,
$ {\boldsymbol{r}} $ are chosen to be spatially on-axis displacements with$ |{\boldsymbol{r}}|/a_s = 0,1,2,3,4,5,6,7 $ . The differences between the different operators can be monitored through the effective masses of the corresponding correlation functions$ C(t) $ of the operators$ \begin{equation} a_t M_{\rm{eff}}(t) = \ln \frac{C(t)}{C(t+1)}. \end{equation} $
(39) $ a_t M_{\rm{eff}}(t) $ of these operators in the$ 0^{-+} $ channel are shown in Fig. 4. The different$ t $ -behaviors of the effective mass plateaus show the different coupling of the operators with different$ |{\boldsymbol{r}}| $ to different intermediate states. For a given quantum number$ J^{PC} $ , the differences among different operators$ O_i $ in an operator set$ \{O_i, i = 1,2,\ldots\} $ can be reflected by their couplings to the orthogonal complete state set$ \{|n\rangle, n = 1,2,\ldots\} $ with the normalization condition$ \langle n|m\rangle = \delta_{mn} $ ,Figure 4. (color online) Effective mass of these correlators with different
$r$ (labelled by$R=r/a_s$ ).${{M_{\rm var}}}$ labels the effective mass of the ground state optimized operator obtained from$3\times 3$ variational analysis.$ \begin{equation} O_i^\dagger|0\rangle\equiv \sum\limits_{n} |n\rangle\langle n|O_i^\dagger|0\rangle\equiv\sum\limits_n W_{in}^*|n\rangle, \end{equation} $
(40) where
$ W_{in} = \langle 0|O_i|n\rangle $ is defined. Therefore, the differences in$ W_{in} $ show how different the operators in this operator set are, and also result in the different$ t $ -behaviors of the effective masses$ M_{\rm{eff}}(t) $ of the corresponding correlation functions in the early time region. In each channel, we focus only on the lowest two states; therefore, we select operators$ {\cal{O}}(r,t) $ with$ r/a_s = 0,3,6 $ to compose an operator set, which are expected to couple to the intermediate states more differently, as manifested by the effective masses of these correlation functions. Based on the operator set in each channel, we first carry out the variational method analysis to obtain the optimized operators that couple most to specific states. That is to say, we calculated the correlation matrix$ \{C_{ij}(t)\} $ of each operator set and solve the generalized eigenvalue problem$ \begin{equation} C_{ij}(t)v_j = \lambda(t,t_0)C_{ij}(t_0)v_j \end{equation} $
(41) to get the eigenvector
$ v_i^{(n)} $ that corresponds to the$ n $ -th largest eigenvalue$ \lambda^{(n)}(t,t_0) $ . It is expected that the operator$ {\cal{O}}^{(n)}(t) = v_i^{(n)}{\cal{O}}(r_i,t) $ couples most with the$ n $ -th lowest state. Thus we have the correlation function$ C^{(n)}(t) $ of the optimized operator$ {\cal{O}}^{(n)} $ ,$ \begin{equation} C^{(n)}(t) = \langle {\cal{O}}^{(n)}(t){\cal{O}}^{(n),\dagger}(0)\rangle\equiv v_i^{(n)}v_j^{(n)}C_{ij}(t), \end{equation} $
(42) whose effective mass function
$ a_t M_{\rm{eff}}^{(n)}(t) $ can be defined similarly to Eq. (39).$ a_t M_{\rm{eff}}^{(n)}(t) $ functions for$ n = 1,2 $ for all the channels are plotted in Fig. 5 (ensemble E1) and Fig. 6 (ensemble E2).$ a_t M_{\rm{eff}}^{(1)}(t) $ and$ a_t M_{\rm{eff}}^{(2)}(t) $ are clearly separated from each other, but still have mild time dependence in the early time range due to slight contamination from higher states. In order to obtain the mass values more precisely, we perform two-mass-term fits to$ C^{(n)}(t) $ Figure 5. (color online) The mass plateaus of the correlation functions of the optimized operators obtained through GEVP method on gauge ensemble E1. In each of the six channels
$J^{PC}=0^{-+},\;1^{--},\;(0,1,2)^{++}$ and$1^{-+}$ , the mass plateaus corresponding to the lowest two states are shown. For each correlation function, a two-mass-term fit is performed with the second mass term being introduced to take into account the residual contamination of higher states. The darker colored bands illustrate the fit results using the corresponding time window.Figure 6. (color online) The mass plateaus of the correlation functions of the optimized operators obtained through GEVP method on gauge ensemble E2. In each of the six channels
$J^{PC} = 0^{-+},\;1^{--},\;(0,1,2)^{++}$ and$ 1^{-+} $ , the mass plateaus corresponding to the lowest two states are shown. For each correlation function, a two-mass-term fit is performed with the second mass term being introduced to take into account the residual contamination of higher states. The darker colored bands illustrate the fit results using the corresponding time window.$ \begin{aligned}[b] C^{(n)}(t) = W_1 \left({\rm e}^{-M_1 t}+{\rm e}^{-M_1 (T-t)}\right)+W_2 \left({\rm e}^{-M_2 t}+{\rm e}^{-M_2 (T-t)}\right), \end{aligned} $
(43) where the second mass term is adopted to account for the higher state contamination.
$ W_1 $ and$ W_2 $ are coefficients of the first mass term and the second mass term respectively. The fit results with the fitted parameters are also plotted in Fig. 5 and Fig. 6 as curves with error bands, where the extensions of the curves illustrate the fit windows. For all the fits, the values of the$ \chi^2 $ per degree of freedom ($ \chi^2/{{dof}} $ ) are around one and exhibit the fit quality. The fitted masses of$ 1P $ ,$ 2P $ charmonium states are tabulated in Table 4, in which the experimental values are also given for comparison.$ J^{PC} $ $ \chi_{c0}^{(')}(0^{++}) $ $ \chi_{c1}^{(')}(1^{++}) $ $ \chi_{c2}^{(')}(2^{++}) $ $ h_c^{(')}(1^{+-}) $ $ m_{\rm{COG}} $ E1 $ M(1P)({\rm{MeV}}) $ 3039.1(4) 3083.8(6) 3109.7(6) 3094.0(7) 3093.2(4) $ M(2P)({\rm{MeV}}) $ 3410(4) 3412(7) 3531(8) 3526(5) 3478(5) E2 $ M(1P)({\rm{MeV}}) $ 3391.8(6) 3433.8(9) 3461.8(7) 3443.8(9) 3444.7(5) $ M(2P)({\rm{MeV}}) $ 3785(6) 3792(9) 3916(11) 3917(6) 3860(6) Exp. $ M(1P)({\rm{MeV}}) $ 3414.7(3) 3510.7(1) 3556.2(1) 3525.4(1) 3525.31(7) $ M(2P)({\rm{MeV}}) $ 3862(51) 3871.7(1) 3922(1) 3898(6) Table 4. The masses of 1P and 2P states derived from ensemble E1 and E2. The masses are converted into the values in physical units. The 'center of gravity' masses are the spin averages of the spin-triplet
$ nP $ charmonium masses. The experimental results are also presented for comparison.The non-relativistic quark model expects that for the same principal quantum number
$ n $ , the$ n^{2S+1}L_J $ multiplet with$ S = 1 $ and$ L\neq 0 $ has a 'center of gravity' mass$ M_{\rm{COG}} $ , which is the spin average mass of this multiplet and should be equal to the mass of the spin singlet counterpart (the derivation of the relation can be found in the Appendix A). For example, for the$ L = 1 $ multiplets$ n^3P_J $ multiplet,$ M_{\rm{COG}} $ is defined as$ \begin{aligned}[b] M_{\rm{COG}}(nP) =& \frac{1}{9}\left[5M(n^3P_2)+3M(n^3P_1)+M(n^3P_0)\right],\\ =& M(n^1P_1). \end{aligned} $
(44) As shown in Table 4, the masses of the
$ 1P $ states are determined very precisely with the statistical error being less than 1 MeV, so we can check the relation of Eq. (44). The difference between the$ M_{\rm{COG}}(nP) $ and the mass of the spin singlet$ h_c(nP) $ is sometimes called the hyperfine splitting of$ nP $ charmonium states, which is denoted by$ \Delta_{\rm{HFS}}(nP) = \Delta_{\rm{HFS}} = M_{h_c}(nP)-M_{\rm{COG}}(nP) $ in this study. On the two ensembles (E1 and E2) in this paper, we obtain$ \Delta_{\rm{HFS}}(1P) $ as$ \begin{aligned}[b] E1:\; \; \Delta_{\rm{HFS}}(1P) =& 0.8\pm 0.8\; {\rm{MeV}},\\ E2:\; \; \Delta_{\rm{HFS}}(1P) =& -0.9\pm 1.0\; {\rm{MeV}}. \end{aligned} $
(45) In other words, the relation Eq. (44) is satisfied for
$ 1P $ states with a high precision. For$ 2P $ states, we have$ \begin{aligned}[b] E1:\; \; \Delta_{\rm{HFS}}(2P) =& 49\pm 7\; {\rm{MeV}},\\ E2:\; \; \Delta_{\rm{HFS}}(2P) =& 57\pm 9\; {\rm{MeV}}. \end{aligned} $
(46) There is a substantial deviation from Eq. (44). We are not sure of the reason for this deviation yet. It is possible that
$ 2P $ charmonium states do have a non-zero hyperfine splitting. It is also possible that the masses of$ 2P $ states are not determined precisely enough. This should be explored in future studies.It is interesting to note that the experimental results support the relation of Eq. (44) to a very high precision [2]. For charmonium systems, the
$ 1P $ states$ \big(h_c(1^1P_1), $ $ \chi_{c0,1,2}(1^3P_{0,1,2})\big) $ have been well established. According to the PDG data, the 'center of gravity' mass of$ 1P $ charmonia is$ M_{\rm{COG}} = 3525.3(1) $ MeV, which is almost the same as the$ h_c $ mass$ M(h_c) = 3525.4(1) $ MeV. For bottomium systems, the$ 1P $ and$ 2P $ states are below the$ B\bar{B} $ threshold and have very small widths. They are approximately stable particles and have direct correspondence to the according states predicted by the non-relativistic quark model. The$ M_{\rm{COG}}(1P) = 9899.9(5) $ MeV and$ M_{\rm{COG}}(2P) = $ $ 10260.3(6) $ also reporduce the$ h_b(1P) $ mass$ M(h_b(1P)) = $ $ 9899.3(8) $ MeV and the$ h_b(2P) $ mass$ M(h_b(2P)) = $ $ 10259.8(1.2) $ MeV.If the relation described by Eq. (44) is somewhat universal, we can use it to make a prediction of the mass of
$ h_c(2P) $ . Experimentally, there are three particles being assigned to be the candidates of the$ \chi_{c0,1,2} $ charmonia, which are$ \chi_{c1}'(3872) $ (the old$ X(3872) $ ),$ \chi_{c2}'(3930) $ and$ \chi_{c0}'(3860) $ , while there is no experimental evidence of$ h_c' $ yet. The resonance parameters of these three states are$ \begin{aligned}[b]& \chi_{c0}'(3860):\;\; M_R = 3860(50){\rm{MeV}},\;\; \Gamma_R\sim 200\; \; {\rm{MeV}},\\& \chi_{c1}'(3872):\;\; M_R = 3871.7(2){\rm{MeV}},\;\; \Gamma_R<1.2\; \; {\rm{MeV}},\\& \chi_{c2}'(3930):\;\; M_R = 3922(1){\rm{MeV}}, \;\; \Gamma_R = 35(3)\; \; {\rm{MeV}}. \end{aligned} $
(47) $ \chi_{c0}'(3860) $ 's width is large, while those of the other two states are relatively small. Using Eq. (44), the mass of$ h_c(2P) $ can be tentatively estimated to be$ \begin{equation} M(h_c(2P)) = M_{\rm{COG}}(2P)\approx 3898(6) \; {\rm{MeV}}. \end{equation} $
(48) -
In the quark model picture, the spectroscopy of charmonia can be studied by solving the non-relativistic Schrödinger equation of bound states with QCD-inspired inter-quark potentials
$ V(r) $ along with the relativistic corrections. To order$ v^2\approx {\boldsymbol{p}}^2/m^2 $ , where$ v $ is the velocity of the (anti-)charm quark with mass$ m $ within a bound state, the generalized Breit-Fermi Hamiltonian [15] is$ \begin{aligned}[b] H =&2m+\frac{{\boldsymbol{p}}^2}{m}-\frac{1}{4m^3}{\boldsymbol{p}}^4+V(r)\\ &+H_{\rm{SI}}+H_{\rm{LS}}+H_{\rm{SS}}+H_{\bf{T}}, \end{aligned}\tag{A1} $
where
$ H_{\bf{SI}} $ is the spin-independent interaction term whose explicit form is irrelevant to the discussion here and is omitted,$ H_{\bf{LS}} $ is the term for the spin-obital coupling,$ H_{\rm{SS}} $ is the spin-spin interaction term, and$ H_{\rm{T}} $ is the tensor interaction part. If the potential$ V(r) $ can be split into the vector-like part$ V_{\rm{V}}(r) $ and scalar-like part$ V_{\rm{S}}(r) $ , the explicit expressions of$ H_{\rm{LS}} $ ,$ H_{\rm{SS} }$ and$ H_{\rm{T}} $ are$ \begin{aligned}[b] H_{\rm{LS}} = &\frac{1}{2m^2 r}\left(3 \frac{\rm d}{{\rm d}r}V_{\rm{V}}-\frac{\rm d}{{\rm d}r}V_{\rm{S}}\right){\boldsymbol{L}}\cdot{\boldsymbol{S}},\\ H_{\rm{SS}} = &\frac{2}{3m^2}{\boldsymbol{S}}_1\cdot{\boldsymbol{S}}_2 \nabla^2 V_{\rm{V}}(r),\\ H_{\rm{T}} = & \frac{1}{12m^2}\left(\frac{1}{r} \frac{\rm d}{{\rm d}r} V_{\rm{V}}-\frac{{\rm d}^2}{{\rm d}r^2} V_{\rm{V}} \right)S_{12}, \end{aligned}\tag{A2} $
with
$ S_{12}\equiv 12\left(\frac{({\boldsymbol{S}}_1\cdot{\boldsymbol{r}})({\boldsymbol{S}}_2\cdot{\boldsymbol{r}})}{r^2}-\frac{1}{3}{\boldsymbol{S}}_1\cdot{\boldsymbol{S}}_2 \right) \tag{A3},$
where
$ {\boldsymbol{S}}_{1,2} $ are the spins of the charm quark and antiquark, and$ {\boldsymbol{S}} = {\boldsymbol{S}}_1+{\boldsymbol{S}}_2 $ is their total spin. For a given state in terms of the eigenvalues$ S,\;L,\;J $ of$ {\boldsymbol{S}} $ , the orbital momentum$ {\boldsymbol{L}} $ and the total angular momentum$ {\boldsymbol{J}} = {\boldsymbol{L}}+{\boldsymbol{S}} $ , the expectation value$ \langle {\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle $ reads$ \langle {\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle = \frac{1}{2}\left[J(J+1)-L(L+1)-S(S+1)\right]. \tag{A4} $
Obviously this expectation value for
$ L = 0 $ or$ S = 0 $ states vanishes. It is easy to see that the expectation value of$ S_{12} $ also vanishes for$ L = 0 $ or$ S = 0 $ . Otherwise the expectation value of$ S_{12} $ reads$ \langle S_{12}\rangle = \frac{4}{(2L+3)(2L-1)}\left[\langle {\boldsymbol{S}}^2 {\boldsymbol{L}}^2\rangle-\frac{3}{2}\langle {\boldsymbol{L}}\cdot{\bf{S}}\rangle-3\langle {\boldsymbol{L}}\cdot{\bf{S}}\rangle^2\right]. \tag{A5}$
As for the spin-spin interaction, if the
$ V_{\rm{V}}(r) $ is taken to be Coulomb-like, namely,$ V_{\rm{V}}\propto 1/r $ , then$ H_{\rm{SS}}\propto \delta^3({\boldsymbol{r}}) {\boldsymbol{S}}_1\cdot{\boldsymbol{S}}_2 $ is actually a contact interaction, whose expectation value vanishes for$ L\neq 0 $ states, since their radial wave function$ \phi_{nl}(r) $ at the origin$ r = 0 $ is zero. For$ L = 0 $ states ($ n^{1}S_0 $ and$ n^{3}S_1 $ states), the spin-spin interaction results in the hyperfine splitting$ \Delta M_{\rm{hfs}} $ between the spin triplet and spin singlet$ S $ states.The values of
$ \langle {\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle $ and$ \langle S_{12}\rangle $ for$ S = 1 $ and$ L\neq 0 $ states are listed in Table A1. It is easy to see that for a$ n^{3}L_J $ super-multiplet with$ J = L-1,\;L,\;L+1 $ , one has$J$ $L-1$ $L$ $L+1$ $\langle {\boldsymbol{L} }\cdot{\boldsymbol{S} }\rangle_J$ $-(L+1)$ $-1$ $L$ $\langle S_{12}\rangle_J$ $-\dfrac{2(L+1)}{2L-1}$ $2$ $-\dfrac{2L}{2L+3}$ Table A1. The expectation values of
$\langle {\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle$ and$\langle S_{12}\rangle$ for$S=1$ and$L\neq 0$ states.$ \begin{aligned}[b] \langle {\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle_{\rm{avg}} \equiv& \frac{1}{3(2L+1)}\sum\limits_J (2J+1)\langle{\boldsymbol{L}}\cdot{\boldsymbol{S}}\rangle_J = 0, \\ \langle S_{12}\rangle_{\rm{avg}} \equiv& \frac{1}{3(2L+1)}\sum\limits_J (2J+1)\langle S_{12}\rangle_J = 0. \end{aligned}\tag{A6} $
Therefore, if one introduces a 'center of gravity' mass
$ M_{\rm{COG}}(nL) $ for$ n^{3}L_J $ states,$ M_{\rm{COG}}\equiv \frac{1}{2(2L+1)}\sum\limits_J (2J+1)M_J(nL), \tag{A7}$
which is the spin averaged mass weighted by the number of polarizations, one should have
$ M_{\rm{COG}} = M_L(n^1L_L), \tag{A8} $
where
$ M_L(n^1L_L) $ is the mass of the spin singlet state of$ nL $ supermultiplet.
Annihilation diagram contribution to charmonium masses
- Received Date: 2021-10-06
- Available Online: 2022-04-15
Abstract: In this work, we generate gauge configurations with